Question

simplified and solving equations determine the value of the unknown in each equation 8(b+1)=-3(2+b)​

Answer 1

Answer:

-14/11

Step-by-step explanation:

As per the provided information in the given question, we have to find the unknown value (value of b) in the given equation.

• $\sf{8(b+1)= -3(2+b)}$

In order to solve this equation, here we'll use transposition method. In transposition method, we transpose the values from RHS to LHS and vice-versa and the arithmetic operations are changed when they are transposed.

$\implies\sf{8(b+1)= -3(2+b)}$

Using the multiplication over addition property in both LHS and RHS to perform multiplication.

$\implies\sf{8(b)+8(1)= -3(2)-3(b)}$

Performing multiplication in LHS and RHS.

$\implies\sf{8b+8= -6-3b}$

Now, transposing like terms. Here, 8b and -3b ; 8 and -6 are like terms. So, we'll transpose -3b from RHS to LHS and 8 from LHS to RHS. Note that, arithmetic operations will get changed while transposing i.e, -3b has minus sign in RHS, so it'll have plus sign in LHS and 8 has plus sign in LHS, so it'll have negative sign in RHS.

$\implies\sf{8b+3b= -6-8}$

Performing addition in LHS and subtraction in RHS.

$\implies\sf{11b= -14}$

Transposing 11 from LHS to RHS. As it is in form of multiplication with b in LHS, so it'll be in the form of division with -14 in RHS.

$\implies\boxed{\sf{\red{b= \dfrac{-14}{11}}}}$

Therefore, the value of b is -14/11.

$\rule{200}2$

Answer 2

Answer:

-14/11

Step-by-step explanation:

As per the provided information in the given question, we have to find the unknown value (value of b) in the given equation.

$\sf{8(b+1)= -3(2+b)}$

In order to solve this equation, here we'll use transposition method. In transposition method, we transpose the values from RHS to LHS and vice-versa and the arithmetic operations are changed when they are transposed.

$\implies\sf{8(b+1)= -3(2+b)}$

Using the multiplication over addition property in both LHS and RHS to perform multiplication.

$\implies\sf{8(b)+8(1)= -3(2)-3(b)}$

Performing multiplication in LHS and RHS.

$\implies\sf{8b+8= -6-3b}$

Now, transposing like terms. Here, 8b and -3b ; 8 and -6 are like terms. So, we'll transpose -3b from RHS to LHS and 8 from LHS to RHS. Note that, arithmetic operations will get changed while transposing i.e, -3b has minus sign in RHS, so it'll have plus sign in LHS and 8 has plus sign in LHS, so it'll have negative sign in RHS.

$\implies\sf{8b+3b= -6-8}$

Performing addition in LHS and subtraction in RHS.

$\implies\sf{11b= -14}$

Transposing 11 from LHS to RHS. As it is in form of multiplication with b in LHS, so it'll be in the form of division with -14 in RHS.

$\implies\boxed{\sf{\red{b= \dfrac{-14}{11}}}}$

Therefore, the value of b is -14/11.

$\rule{200}2$

•@Nish√