simplified form of x^(a+b) .x^(b+c) .x^(c+a) , if a+b+c = 1/6
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x^1/3
Step-by-step explanation:
x^ a+b.x^ b+c.x^ c+a= x^ (a+b+b+c+c+a) (since a^ m.a^ n= a^ m+n)
= x^ (2.a+b+c)
= x^ (2.1/6) ( since a+b+c= 1/3)
= x^ 1/3
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