Question

simplified it then give me solution​

Answer 1

Answer:

sorry i did not understand your question

Answer 2

Answer:

$if\: a + b = ab = \frac{a}{b} \\ then \: find \: a - b \\ sol > \: a + b = ab \\ squaring \: both \: side \\ (a + b) {}^{2} = (ab) {}^{2} \\ {a}^{2} + b {}^{2} + 2ab - {a}^{2} b {}^{2} = 0 \\ {a}^{2} + {b}^{2} + ab(2 - ab) = 0$