Question

Simplified value of
$2 {}^{n} \times 4 {}^{n} \times 8 {}^{1 - n}$


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Answer 1

Step-by-step explanation:

${2}^{n} \times {4}^{n} \times {8}^{1 - n} = > {2}^{n} \times {2}^{2n} \times {2}^{3(1 - n)} \\ \\ \\ = > {2}^{n + 2n + 3 - 3n} = > {2}^{3n - 3n + 3} = > {2}^{3} = > 8$

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