Question

Simplify :-

[1 - {1 -(1 - n)-¹}-1]-1​

Answer 1

Answer:

By remainder theorem we know that when a polynomial f (x) is divided by x – a, then the remainder is f(a).

Let f(x) = 2x3 + 3x2 – 5x – 6

(i) f (-1) = 2(-1)3 + 3(-1)2 – 5(-1) – 6 = -2 + 3 + 5 – 6 = 0

Thus, (x + 1) is a factor of the polynomial f(x).

Selina Concise Mathematics Class 10 ICSE Solutions Remainder and Factor Theorems - 6

Thus, (2x – 1) is not a factor of the polynomial f(x).

(iii) f (-2) = 2(-2)3 + 3(-2)2 – 5(-2) – 6 = -16 + 12 + 10 – 6 = 0

Thus, (x + 2) is a factor of the polynomial f(x).

Answer 2

$\huge{\colorbox{pink}{ Answer }}$

[1-{1-(1-n)-1}-11-1

={1-{1-1/1-n}-11-1

=[1-{1-n-1/1-n}-11-1

=[1-{-n/1-n)-1)-1

=[1+n-1)-1

=[n]-1

=1/n