Math, asked by Aarshit, 15 days ago

Simplify 1/1+2√2-√3


Please solve it fast accurate

Answers

Answered by Anonymous
1

is this accuracy enough?

thanks for asking

Attachments:
Answered by sanvi7031
8

Answer:-

 \dfrac{1}{1 + 2 \sqrt{2} +  \sqrt{3}  }  \times  \dfrac{1 + 2 \sqrt{2} -  \sqrt{3}  }{1 + 2 \sqrt{2 } -  \sqrt{3}  }

\quad

 \dfrac{1 + 2 \sqrt{2}  -  \sqrt{3} }{(1 + 2 \sqrt{2} ) {}^{2} - (3) {}^{2}  }  =  \dfrac{1 + 2 \sqrt{2} -  \sqrt{3}  }{1 + 8 + 4 \sqrt{2} - 3 }

\quad

 =  \dfrac{1 + 2 \sqrt{2} -  \sqrt{3}  }{6 + 4 \sqrt{2} }  \times  \dfrac{6 - 4 \sqrt{2} }{6 - 4 \sqrt{2} }

\quad

 =  \dfrac{6 - 4 \sqrt{2} + 12 \sqrt{2} - 16 - 6 \sqrt{3}   + 4 \sqrt{6}  }{36 - 32}

\quad

 =  \dfrac{ - 10 + 8 \sqrt{2} - 6 \sqrt{3}  + 4 \sqrt{6}  }{4}

\quad

  = \dfrac{ - 5 + 4 \sqrt{2}  - 3 \sqrt{3}  + 2 \sqrt{6} }{2}

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