Question

Simplify:
1.17×{16-(17-2)}=
2.80-{(25-8)+(40-23)}=
3.(30÷6)÷{(6×12)÷8}=
4.{240÷{5(6+3-7)}+17×2+4}=

plese give the answers.​

Answer 1

Answer -

Let's first understand BODMAS :-

• B :- Brackets ( ) { } [ ]
• O :- Of
• D :- Division
• M :- Multiplication
• A :- Addition
• S :- Subtraction

Applying BODMAS rule -

i) 17 × { 16 - ( 17 - 2 ) }

→ 17 × { 16 - ( 15 ) }

→ 17 × { 16 - 15 }

→ 17 × { 1 }

→ 17

ii) 80 - { ( 25 - 8 ) + ( 40 - 23 ) }

→ 80 - { ( 17 ) + ( 17 ) }

→ 80 - { 17 + 17 }

→ 80 - { 34 }

→ 80 - 34

→ 46

iii) ( 30 ÷ 6 ) ÷ { ( 6 × 12 ) ÷ 8 }

→ ( 5 ) ÷ { ( 72 ) ÷ 8 }

→ ( 5 ) ÷ { 9 }

→ 5 ÷ 9

iv) { 240 ÷ { 5 ( 6 + 3 - 7 ) } + 17 × 2 + 4 }

→ { 240 ÷ { 5 ( 9 - 7 ) } + 17 × 2 + 4 }

→ { 240 ÷ { 5 ( 2 ) } + 17 × 2 + 4 }

→ { 240 ÷ 10 + 17 × 2 + 4 }

→ { 24 + 17 × 2 + 4 }

→ { 24 + 34 + 4 }

→ 62

Answer 2

$\large\sf\underline{Question\:1\::}$

• $\sf\:17 \times [16 - (17-2) ]$

$\large\sf\underline{Solution\::}$

$\sf\:17 \times [16 - (17-2) ]$

$\sf\implies\:17 \times [16 - (15) ]$

$\sf\implies\:17 \times [16 - 15 ]$

$\sf\implies\:17 \times [1]$

$\sf\implies\:17 \times 1$

$\small{\underline{\boxed{\mathrm{\implies\:17}}}}$ ★

__________________________‎

$\large\sf\underline{Question\:2\::}$

• $\sf\:80-[(25-8) +(40-23) ]$

‎

$\large\sf\underline{Solution\::}$

$\sf\:80-[(25-8) +(40-23) ]$

$\sf\implies\:80-[(17) +(17) ]$

$\sf\implies\:80-[17 +17 ]$

$\sf\implies\:80-[34 ]$

$\sf\implies\:80-34$

$\small{\underline{\boxed{\mathrm{\implies\:46}}}}$ ★

__________________________‎

$\large\sf\underline{Question\:3\::}$

• $\sf\:(30 \div 6) \div [(6 \times 12) \div 8]$

‎

$\large\sf\underline{Solution\::}$

$\sf\:(30 \div 6) \div [(6 \times 12) \div 8]$

$\sf\implies\:\frac{30}{6} \div [(6 \times 12) \div 8]$

$\sf\implies\:\cancel{\frac{30}{6}} \div [(6 \times 12) \div 8]$

$\sf\implies\:5 \div [(6 \times 12) \div 8]$

$\sf\implies\:5 \div [72 \div 8]$

$\sf\implies\:5 \div \frac{72}{8}$

$\sf\implies\:5 \div \cancel{\frac{72}{8}}$

$\sf\implies\:5 \div 9$

$\small{\underline{\boxed{\mathrm{\implies\:\frac{5}{9}}}}}$ ★

__________________________‎

$\large\sf\underline{Question\:4\::}$

• $\sf\:[240 \div [5(6+3-7) ]+17 \times 2+4]$

‎

$\large\sf\underline{Solution\::}$

$\sf\:[240 \div [5(6+3-7) ]+17 \times 2+4]$

$\sf\implies\:[240 \div [5(9-7) ]+17 \times 2+4]$

$\sf\implies\:[240 \div [5(2)]+17 \times 2+4]$

$\sf\implies\:[240 \div [5 \times 2]+17 \times 2+4]$

$\sf\implies\:[240 \div [10]+17 \times 2+4]$

$\sf\implies\:[240 \div 10+17 \times 2+4]$

$\sf\implies\:[\frac{240}{10}+17 \times 2+4]$

$\sf\implies\:[\cancel{\frac{240}{10}}+17 \times 2+4]$

$\sf\implies\:[24+17 \times 2+4]$

$\sf\implies\:[24+34+4]$

$\sf\implies\:[58+4]$

$\small{\underline{\boxed{\mathrm{\implies\:62}}}}$ ★

__________________________‎

$\large\sf\underline{More\:to\:know\::}$

In solving all these problems we have followed BODMAS.

BODMAS rule states that in an expression containing multiple arithmetic operations , there is an order in which they are to be solved.

The order for solving them is provided by BODMAS. The order is as follows :

• B which means simplification of brackets

• O order or exponents

• D for division

• M for multiplication

• A for addition

• S for subtraction

__________________________‎

Note :- In place of third bracket {} I have used fourth bracket [] !

!! Hope it helps !!‎