Question

simplify [(1/2)²-(1/4)³×2³]
please​

Answer 1

Answer:

(a+ b+ c)³= (a³+ 3a²b+ 3ab²+ b³)+ 3(a²+ 2ab+ b²)c+ 3(a+ b)c2+ c³

(a+ b+ c)³= a³+ b³+ c³+ 3a²b+ 3a²c+ 3ab²+ 3b²c+ 3ac²+ 3bc²+ 6abc

(a+ b+ c)³= (a³+ b³+ c³)+ (3a²b+ 3a²c+ 3abc)+ (3ab²+ 3b²c+ 3abc)+ (3ac²+ 3bc²+ 3abc)−3abc

(a+ b+ c)³= (a³+ b³+ c³)+ 3a(ab+ ac+ bc)+ 3b(ab+ bc+ ac)+ 3c(ac+ bc+ ab)−3abc

(a+ b+ c)³= (a³+ b³+ c³)+ 3(a+ b+ c)(ab+ ac+

bc)−3abc

(a+ b+ c)³= (a³+ b³+ c³)+ 3[(a+ b+ c)(ab+ ac+

bc)−abc]

Step-by-step explanation:

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