Math, asked by kanhaiyaklsiet7518, 5 months ago

simplify [{1^2+2^2+3^2+4^2}^(1/3)]*[{1^3+2^3+3^3+4^3}^(1/3)]*{2^2+3^2-5*2}(2/3)

Answers

Answered by ShauryaSaxena007
1

ANSWER:30

STEP BY STEP EXPLANATION:

(1^2+2^2+3^2+4^2)^1/3

=(1+4+9+16)^1/3

=30^1/3

(1^3+2^3+3^3+4^3)^1/3

1+8+27+64

=100

=100^1/3

(2^2+3^2-5*2)^2/3

(4+9-10)^2/3

=3^2/3

=30^1/3*100^1/3*3^2/3

=3000^1/3*3^2/3 (∵a^n*b^n=(ab)^n)

=3000^1/3*9^1/3

=27000^1/3 (∵a^n*b^n=(ab)^n)

=∛27000

=30

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