Question

simplify 1/2 root 486-root 27/2

Answer 1

please mark it brainlist

Answer 2

The value of $\dfrac{1}{2}\sqrt{486}-\sqrt{\dfrac{27}{2}}=3\sqrt{6}$.

Step-by-step explanation:

We have,

$\dfrac{1}{2}\sqrt{486}-\sqrt{\dfrac{27}{2}}$

To find, the value of $\dfrac{1}{2}\sqrt{486}-\sqrt{\dfrac{27}{2}}=?$

∴ $\dfrac{1}{2}\sqrt{486}-\sqrt{\dfrac{27}{2}}$

$=\dfrac{1}{2}\sqrt{486}-\sqrt{\dfrac{27}{2}}\times\sqrt{\dfrac{2}{2}}$

$=\dfrac{1}{2}\sqrt{486}-\dfrac{\sqrt{27\times2} }{2}$

$=\dfrac{1}{2}\sqrt{81\times 6}-\dfrac{3\sqrt{6}}{2}$

$=\dfrac{9}{2}\sqrt{ 6}-\dfrac{3\sqrt{6}}{2}$

$=\dfrac{6\sqrt{6}}{2}$

$=3\sqrt{6}$

Hence, the value of $\dfrac{1}{2}\sqrt{486}-\sqrt{\dfrac{27}{2}}=3\sqrt{6}$.