Math, asked by Faiqa93, 11 months ago

Simplify : [1^3+2^3+3^3+4^3+5^3]^1/2

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Anonymous: Mark it as brainlist if it helps you:-)

Answers

Answered by Anonymous
1

Given \:  \: Question \: Is \:  \:  \\  \\ (1 {}^{3}  + 2 {}^{3}  + 3 {}^{3}  + 4 {}^{3}  + 5 {}^{3} ) {}^{ \frac{1}{2} }  \\  \\ Answer \:  \\  \\ we \: know \: that \: sum \: of \: cubes \: of \: natural \:  \\ numbers \: is \: given \: by \:  \frac{(n(n + 1)) {}^{2} }{4}  \\ where \: n \: is \: number \: of \: terms. \\  \\ here \: n \:  = 5 \\  \\ so \: sum \: of \: this \: series \: is \: given \: by \:  \\  \\ ( \frac{(5(5 + 1)) {}^{2} }{4} ) {}^{ \frac{1}{2} }  \\  \\ ( \frac{(30) {}^{2} }{4} ) {}^{ \frac{1}{2} }  \\  \\  \frac{((30) {}^{2} ) {}^{ \frac{1}{2} } }{4 {}^{ \frac{1}{2} } }  \\  \\   \frac{30}{(2 {}^{2} ) {}^{ \frac{1}{2} } }  \\  \\  \frac{30}{2}  \\  \\  = 15


suchitrabanik56: very good
suchitrabanik56: are you PhD in mathematics??????
Faiqa93: Are you sure about this method because its class 9 question and we are not taught by this method
Anonymous: yeah! it's Quite Easy and Simple to understand:-)
Faiqa93: Okay thank you!
Answered by aganc03
2

[1^3+2^3+3^3+4^3+5^3]^1/2

= [1+8+27+64+125]^1/2

= [225]^1/2

= 15

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