Math, asked by sridharbehera1851985, 23 days ago

Simplify :
1.) (3z-4y)^3-(3x+4y)^3​

Answers

Answered by 8edivyanshmishra
0

Answer:

0

Step-by-step explanation:

the Answer is 0 itself

Answered by sudiptakotal02
1

Answer:

27(z^3-x^3)-128y^3-108y(z^2-x^2)+144y^2(z-x)

Step-by-step explanation:

We know,

(a+b)^3=a^3+b^3+3a^2b+3ab^2

(a-b)^3=a^3-b^3-3a^2b+3ab^2

So,

(3z-4y)^3-(3x+4y)^3

=(27z^3-64y^3-108z^2y+144zy^2)-(27x^3+64y^3+108z^2y+144zy^2)

=27z^3-64y^3-108z^2y+144zy^2-27x^3-64y^3-108z^2y-144zy^2

=27(z^3-x^3)-128y^3-108y(z^2-x^2)+144y^2(z-x)

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