Math, asked by nskamboj2004, 7 months ago

Simplify
1 ...4/9
2 ....35/111
3 .....18/13
4.......41/16
5.......101/11
6........13/17

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Answers

Answered by anindyaadhikari13
4

\star\:\:\bf\large\underline\blue{Question:-}

  • Simplify the problems.

\star\:\:\bf\large\underline\blue{Solution:-}

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 \sqrt{ \frac{80}{105} }

 =  \sqrt{ \frac{ \cancel{5 }\times 16}{ \cancel{5 }\times 81} }

 =  \sqrt{ \frac{16}{81} }

 =  \sqrt{ (\frac{4}{9})^{2}  }

 =  \pm  \frac{4}{9}

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 \sqrt{ \frac{1225}{12321} }

 =  \sqrt{ \frac{35 \times 35}{111 \times 111} }

 =  \sqrt{( \frac{35}{111})^{2}  }

 =  \pm \frac{35}{111}

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 \sqrt{1 \frac{155}{169} }

 =  \sqrt{ \frac{(1 \times 155) + 169}{169} }

 =  \sqrt{ \frac{155 + 169}{169} }

 =  \sqrt{ \frac{324}{169} }

 \sqrt{( \frac{18}{13})^{2}  }

 =  \pm \frac{18}{13}

 =  \pm1 \frac{5}{18}

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 \sqrt{6 \frac{145}{256} }

 =  \sqrt{ \frac{(6 \times 256) + 145}{256} }

 =  \sqrt{ \frac{1681}{256} }

 =  \sqrt{ {( \frac{41}{16}) }^{2} }

 =  \pm \frac{41}{16}

 =  \pm2 \frac{9}{16}

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 \sqrt{84 \frac{37}{121} }

 =  \sqrt{ \frac{(84 \times 121) + 37}{121} }

 =  \sqrt{ \frac{10201}{121} }

 =  \sqrt{ {( \frac{101}{11}) }^{2} }

 =  \pm \frac{101}{11}

 =  \pm9 \frac{2}{11}

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 \sqrt{ \frac{1183}{2023} }

 =  \sqrt{ \frac{169 \times  \cancel{7}}{289 \times \cancel{ 7}} }

 =  \sqrt{ (\frac{13}{17})^{2} }

 =  \pm \frac{13}{17}

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