Question

Simplify 1/ 7+4 root 3 +1/7- 4 root 3

Answer 1

The solution is being provided above.

Answer 2

$Given \: \frac{1}{(7+4\sqrt{3})} + \frac{1}{(7-4\sqrt{3})}$

$= \frac{ 7-4\sqrt{3} + 7 + 4\sqrt{3}}{(7+4\sqrt{3})(7-4\sqrt{3})}$

$= \frac{14}{7^{2} - (4\sqrt{3})^{2}}$

$= \frac{14}{49 - 48}$

$= \frac{14}{1}$

$= 14$

Therefore.,

$\red{\frac{1}{(7+4\sqrt{3})} + \frac{1}{(7-4\sqrt{3})}}$

$\green { = 14}$

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