Math, asked by swad, 1 year ago

simplify [1/(a-b)(a-c)]+[1/(b-c)(b-a)]+[1/(c-a)(b-c)

Answers

Answered by bans55
0

 \frac{1}{(a - b) \times (a - c)}  \times  \frac{(b - c)}{(b - c)}  \:  \:  \:  +  \:  \:  \:  \frac{1}{(b - c) \times (b - a)}  \times  \frac{(a - c)}{a - c}  \:  \:  \:  +  \:  \:  \frac{1}{(c - a) \times(b - c)}  \times  \frac{(a - b)}{(a - b)}
[(b-c) - (a-b) - (a-c)]/[(a-b)(b-c)(c-a)]

 \frac{ - 3a - 2c}{(a - b)(b - c)(c - a)}
Is the answer.


swad: answer is wrong
bans55: I'm sorry. please correct
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