Simplify (1/cos theta+sin theta/cos theta)(1-sin theta/cos theta)
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Answered by
13
Let theta=x
=(1/cosx+sinx/cosx)(1-sinx/cosx)
=(1+sinx/cosx)(1-sinx/cosx)
=[(1-sinx)]^2/cos^2x
=Cos^x/cos^2x
=1
=(1/cosx+sinx/cosx)(1-sinx/cosx)
=(1+sinx/cosx)(1-sinx/cosx)
=[(1-sinx)]^2/cos^2x
=Cos^x/cos^2x
=1
Answered by
4
Answer:
1
Step-by-step explanation:
(1/cos theta + sin theta/cos theta)(1-sin theta/cos theta)
(sec theta + tan theta)(1/cos theta - sin theta/cos theta)
(sec theta + tan theta)(sec theta - tan theta)
sec2 theta - tan2 theta
1
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