Question

simplify
(1+cot^2 theta) (1-cos theta) (1+cos theta)

pls help​

Answer 1

Answer:

Given:

$(1 + { \cot^{2} ∅})(1 - \cos∅)(1 + \cos∅) \\ = { \csc^{2} ∅ } \times (1 - \cos^{2} ∅) \\ = \frac{1}{ \sin^{2} ∅ } \times \sin^{2} ∅ = 1 \\ \\ \\ as \: we \: know \: \sin^{2} ∅+ \cos^{2} ∅ = 1 \: and \: \csc∅ = \frac{1}{ \sin∅}$

As the rule of a²-b²=(a+b)(a-b)

1+cot²∅=cosec²∅

Hope you understand.

Answer 2

Answer:

are you are you tuber please say