Question

simplify : ( 1 + cot² theta ) ( 1 - cos theta ) ( 1 + cos theta ) ​

Answer 1

Step-by-step explanation:

L.H.S. = (1+cot

2

θ)(1−cosθ)(1+cosθ)

⇒ L.H.S. = (1+cot

2

θ)(1−cos

2

θ)

⇒ L.H.S. = cosec

2

θsin

2

θ

[∵1+cot

2

θ=cosec

2

θand1−cos

2

θ=sin

2

]

⇒ L.H.S. = cosec

2

θsin

2

θ

⇒ L.H.S. =

sin

2

θ

1

×sin

2

θ=1=R.H.S. [∵cosecθ

sinθ

1

∴cosec

2

θ

sinθ

1

]

Answer 2

Step-by-step explanation:

1 + cot²x (1-cos²x)

cot²x - cos²x -cos²cot²x + 1

cos²x/sin²x - cos²x - cos⁴x /sin²x + 1

Aage tum solve karo