Question

simplify: (1+i^2)÷1-i^2​

Answer 1

Answer:

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Answer:

$\frac{1 + {i}^{2} }{1 - {i}^{2} } \times \frac{1 + {i}^{2} }{1 + {i}^{2} }$

Step-by-step explanation:

As we know that i²=-1

1+i²/1-i²=1+(-1)²/1-(-1)²=2/0=0

Answer 2

Answer:

i² will become -1..

and therefore 1+i²=1-1=0..

and similarly 1-i² =1+1=2

hence 0/2 is ultimately 0