Question

Simplify (1+tan2α)(1-sinα)(1+sinα)

Answer 1

$\underline{\mathfrak{\huge{Answer :-}}}$

Given,

${(1+tan^2 a)(1-sin a)(1+sin a)}$

==> ${(1+tan^2 a)(1-sin^2 a)}$

==> ${1+tan^2 a)(cos^2 a)}$

==> ${cos^2 a + tan^2 a * cos^2 a}$

==> ${cos^2 a + sin^2 a}$ [ ${tan^2 a =}$ ${\frac{sin^2 a}{cos^2 a}}$ ]

==> 1 [ Since ${cos^2 a + sin^2 a = 1}$ ]

$\underline{(1+tan^2 a)(1+sin a)(1-sin a) = 1}$

$\underline{\mathfrak{\huge{Thank You}}}$

Answer 2

hey maye here is the answer is 1