Question

Simplify 1/x^2-5x+6 + 1/x^2-3x+2 - 1/x^2-8x+15

Answer 1

hope it will helps you..............

Answer 2

The answer is $\frac{1}{x^{2} }-16x+23$.

Step-by-step explanation:

The polynomial is given as 1/x^2-5x+6 + 1/x^2-3x+2 - 1/x^2-8x+15.

Now,

$\frac{1}{x^{2} } -5x+6+\frac{1}{x^{2} } -3x+2-\frac{1}{x^{2} } -8x+15\\=\frac{1}{x^{2} }-\frac{1}{x^{2} }+\frac{1}{x^{2} }-5x-3x-8x+6+2+15\\=\frac{1}{x^{2} }-8x-8x+8+15\\=\frac{1}{x^{2} }-16x+23$

Here, we have taken all the terms which are somewhat similar together so that further calculations can be done. $\frac{1}{x^{2} }$ terms are taken together so that one of the $\frac{1}{x^{2} }$ can be cancelled out by subtracting from another $\frac{1}{x^{2} }$, so that only one $\frac{1}{x^{2} }$ is left out. The terms with x having different coefficients is taken together so that further calculations can be applied. Also terms containing only numbers which zero powers of x is taken together for applying further calculations.

Hence, the answer is $\frac{1}{x^{2} }-16x+23$.

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