Question

simplify : 1 - ( x -2) - [( x - 3 )- ( x - 1 ) ] = 0​

Answer 1

Answer:

Given equation: 3/3x + 1/(x + 4) = 10/7x.

⇒ 1/x + 1/(x + 4) = 10/7x.

Now, rearranging the equation, we get:

⇒ {(x + 4) + x} / x(x + 4) = 10/7x

⇒ 2x + 4 / x(x + 4) = 10/7x

⇒ 2x + 4 / x + 4 = 10/7 (Cancelling x on both sides)

Cross multiplying the numerators and denominators of both the sides:

⇒ 7(2x + 4) = 10(x + 4)

⇒ 14x + 28 = 10x + 40

⇒ 4x = 12

⇒ x = 3

Answer 2

Answer:

-5

Step-by-step explanation:

1-(x-2)-[(x-3)-(x-1)] = 0

= 1 -(x -2) - ( x - 3 - x + 1) = 0

= 1 - x + 2 + 3 - 1 = 0

= 3 + 2 - x = 0

= 5 - x = 0

= x = -5