Question

simplify: [11/8×(-6/33)]+[1/3+(3/5÷9/20)]-[4/7×-7/5]​

Answer 1

Answer:

0.5535 is the ans pls like it

Answer 2

To solve : $[\frac{11}{8}\times (\frac{-6}{33} )] + [\frac{1}{3} + (\frac{3}{5} \div \frac{9}{20} )] - [\frac{4}{7} \times (\frac{-7}{5} )]$

Solution:-

• To solve the above equation we will follow BODMAS rule.

• It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

• where,  

       $\begin{array}{l} \\B=brackets \\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { Division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

• According to above rule we will solve.
• $[\frac{11}{8}\times (\frac{-6}{33} )] + [\frac{1}{3} + (\frac{3}{5} \div \frac{9}{20} )] - [\frac{4}{7} \times (\frac{-7}{5} )]$

       $=[\frac{1}{8} \times \frac{-6}{3} ] + [ \frac{1}{3} + (\frac{3}{5} \times \frac{20}{9} ) ] -[\frac{-4}{5} ] \\\\= [\frac{-1}{4} ] + [\frac{1}{3} + \frac{4}{3} ] +\frac{4}{5} \\\\=\frac{-1}{4} + \frac{5}{3} + \frac{4}{5} \\\\=\frac{-15 + 100 +48 }{60} \\\\=\frac{133}{60} \\\\=2.216$

Hence , value of given expression is $\frac{133}{60}$ or $2.216$.