Simplify: -12√6+20√6
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To get the point of intersection, we have to solve the equation of line Y+x=2and parabola y2=x.
On solving them we find the coordinates of points of intersection as (4,−2) and (1,1). Drawing perpendiculars from these points on y-axis, we obtain the coordinate as (0,1) and (0,−2).
Thus, required area =∫−21(2−y−y2)dy=[2y−2y2−3y3]1−−2
=(2−21−31)−(4−−24+83)
=2−65+6−38=8−621=627
=29sq.units.
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