Simplify (12rais to the power1/5 / 27rais to the power1/5)rais to the power 5/2
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[(12)^1/5/ (27)^1/5]^5/2
[(12/27)^1/5]^5/2
[12/27]^1/5×5/2
[12/27]^1/2
√12/√27
2√3/3√3
(2/3)^1/3.
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(12^1/5 ÷ 27^1/5)^5/2
= {(12÷5)^1/5}^5/2
= (12÷27)^1/2. {(a^x)^y = a^xy}
=√12÷√27
=2√3÷3√3
=2÷3 Ans
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