Question

Simplify 13/11×-14/5+13/11×-7/5+-13/11×34/5

Answer 1

 $\frac{13}{11}$ × (-$\frac{14}{5}$ ) + $\frac{13}{11}$× ( - $\frac{7}{5}$ ) + ( - $\frac{13}{11}$) × $\frac{34}{5}$

⇒ $\frac{13}{11}$ { ( - $\frac{14}{5}$) + ( - $\frac{7}{5}$) - ( $\frac{34}{5}}$)}

⇒ $\frac{13}{11}$ ( $\frac{14-7-34}{5}$ )

⇒ $\frac{13}{11}$ ( - $\frac{55}{5}$ )

⇒$\frac{13}{11}$ ( - $11$)

⇒  ( -13)

Ans :- ( 13/11×-14/5+13/11×-7/5+-13/11×34/5 ) = ( -13)

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Answer 2

$\boxed{\dfrac{13}{11}\times (-\dfrac{14}{5})+\dfrac{13}{11}\times (-\dfrac{7}{5})+(-\dfrac{13}{11})\times \dfrac{34}{5}=-13}$

Step-by-step explanation:

Now, $\dfrac{13}{11}\times (-\dfrac{14}{5})+\dfrac{13}{11}\times (-\dfrac{7}{5})+(-\dfrac{13}{11})\times \dfrac{34}{5}$

Step 1. We use the algebraic property $(-a)\times b=a\times b=-(a\times b)$.

$\dfrac{13}{11}\times (-\dfrac{14}{5})+\dfrac{13}{11}\times (-\dfrac{7}{5})+\dfrac{13}{11}\times (-\dfrac{34}{5})$

Step 2. Since $\dfrac{13}{11}$ is common in all the terms, we take it common. Also, use $(+)(-)=(-)$.

$\dfrac{13}{11}\times (-\dfrac{14}{5}-\dfrac{7}{5}-\dfrac{34}{5})$

Step 3. Since all the terms inside the brackets have $5$ in their denominator, so their LCM is $5$.

$\dfrac{13}{11}\times (\dfrac{-14-7-34}{5})$

$=\dfrac{13}{11}\times (-\dfrac{55}{5})$

$=\dfrac{13}{11}\times (-11)$

$=\bold{-13}$

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