Math, asked by bala5173, 3 months ago

simplify 15(y-4)+2(y-9)+(y+6)=0​

Answers

Answered by tennetiraj86
4

Step-by-step explanation:

Given:-

15(y-4)+2(y-9)+(y+6)=0

To find:-

simplify 15(y-4)+2(y-9)+(y+6)=0

Solution:-

Given equation is 15(y-4)+2(y-9)+(y+6)=0

=>15y-60+2y-18+y+6=0

=>(15y+2y+y)+(-60-18+6)=0

=>18y-72=0

=>18y=72

=>y=72/18

=>y=4

Answer:-

The value of y=4

Check :-

LHS:-15(y-4)+2(y-9)+(y+6)

=>15(4-4)+2(4-9)+(4+6)

=>15(0)+2(-5)+10

=>0-10+10

=>0

=RHS

LHS=RHS is true for y=4

Answered by SyedNomanShah
9

\huge\star\mathfrak\red{{Hey Mate...!!}}

=> 15(y-4)+2(y-9)+(y+6)=0

=> 15y-60 + 2y-18 + y+6 = 0

=> 15y+2y+y -60-18+6 = 0

=> 18y - 78 + 6 = 0

=> 18y - 72 = 0

=> 18y = 72

=> y = 72/18

=> y = 12/3

=> y = 4

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