Question

simplify 15(y-4)+2(y-9)+(y+6)=0
Can anyone tell the answer​

Answer 1

$\huge\star\mathfrak\red{{Hey Mate...!!}}$

=> 15(y-4)+2(y-9)+(y+6)=0

=> 15y-60 + 2y-18 + y+6 = 0

=> 15y+2y+y -60-18+6 = 0

=> 18y - 78 + 6 = 0

=> 18y - 72 = 0

=> 18y = 72

=> y = 72/18

=> y = 12/3

=> y = 4 Answer.

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

15(y-4)+2(y-9)+(y+6)=0

Step 1: first we will expanding the terms

➠15×y-4×15+2×y-9×2+y+6=0

➠15y-60+2y-18+y+6=0

Now, terms are unarranged so ,we first arrange the term by placing like terms together means terms of same Variable together.

➠15y+2y+y-60-18+6=0

Solving constant term

Concept: plus minus =minus

minus minus =plus (but we put sign of -)

➠15y+2y+y -78+6=0

➠15y+2y+y -72=0

solving first term or Variable terms

➠18y-72=0

-72 is negative on the left side when we shifts it towards right side it's sign gets changed.

➠18y=72

we know 72 comes up in multiples of 18

➠y=72÷18=4

y=4

Check

15(y-4)+2(y-9)+(y+6)=0

=>15(4-4)+2(4-9)+(4+6)

=>15×0+2×-5+10

=>0-10+10=0+0=0