Simplify? 16-[5-2+{7of2-(6÷3×2-1+3)}] ?
Answers
Answered by
15
Solution :
16-[5–2+{7of2-(2*2–1+3)}]
= 16-[5–2+{7 of 2-(4–1+3)}]
= 16-[5–2+{7 of 2–6}]
= 16-[5–2+{7*2–6}]
= 16-[5–2+{14–6}]
= 16-[5–2+8]
= 16–11
= 5
Answer:
5 ..
Verified Answer
Answered by
4
Answer:
hey mate your answer is 5
Step-by-step explanation:
hey dear you have to do the work of 1st bracket,so
=16-[5-2+{7of 2-(6÷3×2-1+3)}]
=16-[5-2+{7 of 2-6}]
then do the work of 2nd bracket,so
=16-[5-2+{7of 2-6}]
=16-[5-2+8]
then do the work of 3rd and last bracket,so
=16-[5-2+8]
=16-11
then at last do the left sum,so
=16-11
=5
hope it's heps
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