Math, asked by punnyasethi, 3 months ago

simplify (16a4b−2c6)1/2 (27a−6b9c3)−1/3

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Answered by nittalard
0

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Calculus

 

Simplify (27a^-3b^6c^3)^(1/3)

(27a−3b6c3)13(27a-3b6c3)13

Rewrite the expression using the negative exponent rule b−n=1bnb-n=1bn.

(271a3b6c3)13(271a3b6c3)13

Combine 2727 and 1a31a3.

(27a3b6c3)13(27a3b6c3)13

Combine 27a327a3 and b6b6.

(27b6a3c3)13(27b6a3c3)13

Combine 27b6a327b6a3 and c3c3.

(27b6c3a3)13(27b6c3a3)13

Use the power rule (ab)n=anbn(ab)n=anbn to distribute the exponent.

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2713(b6)13

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