Simplify 1by√6+√5-√11
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= 1(√6+√5-√11)
Here,we need to rationalise the denominator.
Rationalising factor = √6+√5+√11
= 1/(√6+√5-√11) × (√6+√5+√11)/(√6+√5+√11)
=1(√6+√5+√11)/(√6+√5-√11)(√6+√5+√11)
=(√6+√5-√11)/[(√6+√5)²-(√11)²]
=(√6+√5-√11)/[(√6²+√5²+2(√6)(√5)) - √11²]
=(√6+√5-√11)/[(6+5+2√30 - 11)]
=(√6+√5-√11)/(11+2√30-11)
=(√6+√5-√11)/2√30
The denominator is still irrational, so we need to rationalise it further.
Now,the rationalising factor = √30
=(√6+√5-√11)/2√30 × √30/√30
=(√6+√5-√11)(√30)/(2√30)(√30)
=(√6×30+√5×30-√11×30)/2√30²
=(√6×6×5+√5×5×6-√330)/2(30)
=(6√5+5√6-√330)/60
Now,the denominator is rationalised.
Hence,it is simplified.
✪hope it helps✪
✰Snehitha✰
✰Brainly benefactor✰
Here,we need to rationalise the denominator.
Rationalising factor = √6+√5+√11
= 1/(√6+√5-√11) × (√6+√5+√11)/(√6+√5+√11)
=1(√6+√5+√11)/(√6+√5-√11)(√6+√5+√11)
=(√6+√5-√11)/[(√6+√5)²-(√11)²]
=(√6+√5-√11)/[(√6²+√5²+2(√6)(√5)) - √11²]
=(√6+√5-√11)/[(6+5+2√30 - 11)]
=(√6+√5-√11)/(11+2√30-11)
=(√6+√5-√11)/2√30
The denominator is still irrational, so we need to rationalise it further.
Now,the rationalising factor = √30
=(√6+√5-√11)/2√30 × √30/√30
=(√6+√5-√11)(√30)/(2√30)(√30)
=(√6×30+√5×30-√11×30)/2√30²
=(√6×6×5+√5×5×6-√330)/2(30)
=(6√5+5√6-√330)/60
Now,the denominator is rationalised.
Hence,it is simplified.
✪hope it helps✪
✰Snehitha✰
✰Brainly benefactor✰
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