Question

simplify (2-√2/2+√2) + (2+√2/2-√2)​

Answer 1

Answer:

Let (2,1) be point A.

(2,1) is at a distance of 23 units from point Q(a,b).

Line AQ is parallel to x−y=4

Slope of line AQ =b−1a−2=1

b=a−1 ----(1)

Also, (2,1) is at a distance of 23 units from point Q(a,b).

So, 23=(a−2)2+(b−1)2

Squaring,

12=(a−2)2+(b−1)2

Subsituting equation(1),

12=(a−2)2+(a−1−1)2

12=2(a−2)2

a−2=±6

a=2±6

In third quadrant a=2−6,

b=1−6

The required line passes through (a,b) and has slope m=−1, since it is perpendicular to L.

So, the equation is y−(1−6)=−1(x−2