Question

simplify (2/3)-1÷(-5/2)-1)-1​

Answer 1

Following are the step for getting the answer:

Given:

$\frac{2}{3} -1\div(\frac{-5}{2}-1 )-1$

to find:

$\frac{2}{3} -1\div(\frac{-5}{2}-1 )-1$=?

Solution:

we have to solve the given expression

we will solve it by BODMAS

B bracket

O of or order

D division

M multiplication

A addition

S subtraction

now,

$\frac{2}{3} -1\div(\frac{-5}{2}-1 )-1$

if there is nothing in denominator there is one so we can write this

like,

$=\frac{2}{3} -\frac{1}{1} \div(\frac{-5}{2}-\frac{1}{1} )-1\\\\so,\\\\=\frac{2}{3} -\frac{1}{1} \div(\frac{-5-2}{2} )-1\\\\=\frac{2}{3} -\frac{1}{1} \div(\frac{-7}{2} )-1\\\\=\frac{2}{3} -\frac{1}{1} \div\frac{-7}{2} -1\\\\=\frac{2-3}{3} \div\frac{-7}{2} -\frac{1}{1} \\\\=\frac{-1}{3} \div\frac{-7}{2} -\frac{1}{1} \\\\=\frac{-1}{3} \div\frac{-7-2}{2} \\\\=\frac{-1}{3} \div\frac{-9}{2} \\\\=\frac{-2+27}{6} \\\\=\frac{25}{6}$

Thus, the answer is 25/6

Answer 2

Answer:

The answer is $\frac{-1}{21}$.

Step-by-step explanation:

To solve any calculation, we use the BODMAS rule.

B - Bracket

O - Orders

D - Division

M - Multiplication

A - Addition

S - Subtraction.

Given $(\frac{2}{3})-1\div (\frac{-5}{2}-1)-1$

Complete the calculation inside the brackets first,

$(\frac{2}{3})-1\div (\frac{-5-2}{2})-1$

$(\frac{2}{3})-1\div \frac{-7}{2}-1$

Now, complete the division.

$\frac{2}{3}-\frac{1}{\frac{-7}{2}}-1$

$\frac{2}{3}+\frac{2}{7}-1$

Now complete the addition,

$\frac{14+6}{21}-1$

$\frac{20}{21}-1$

$\frac{20-21}{21} =\frac{-1}{21}$.