Question

simplify (2+√3)×(2-√3)​

Answer 1

4-2underoot3+2underroot3-3 =4-3= 1 answer

Answer 2

$\huge \bold \color{green}{ \underline{ \underline \red{required \: answer : }}}$

$(2 + \sqrt{3} ) \times (2 - \sqrt{3} )$

now..solve by using property

${a}^{2} - {b}^{2} = (a + b)(a - b)$

$\implies \: (2 + \sqrt{3} )( 2 - \sqrt{3} ) = {2}^{2} - { (\sqrt{3}) }^{2} \\ \\ \implies \: (2 + \sqrt{3} )(2 - \sqrt{3} ) = 4 - 3 \\ \\ \implies \: (2 + \sqrt{3} )(2 - \sqrt{3} ) = 1$

so the answer is 1

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${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab \\ \\ {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ \\(x + a)(x + b) = {x}^{2} + (a + b)x + ab\\ \\ {(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca \\ \\ {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \\ \\ {(a - b)}^{3} = {a}^{3} - {b}^{3} - 3ab(a - b) \\ \\ {a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab) \\ \\ {a}^{3} - {b}^{3} = (a + b) ( {a}^{2} + {b}^{2} + ab)$