simplify 2/3 - 5/6 + 5/12
Answers
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "/-5" was replaced by "/(-5)".
Step by step solution :
Step 1 :
5
Simplify —
6
Equation at the end of step 1 :
2 5
— + — ÷ -5 ÷ 12
3 6
Step 2 :
5
Divide — by -5
6
Equation at the end of step 2 :
2 -1
— + —— ÷ 12
3 6
Step 3 :
-1
Divide —— by 12
6
Equation at the end of step 3 :
2 -1
— + ——
3 72
Step 4 :
2
Simplify —
3
Equation at the end of step 4 :
2 -1
— + ——
3 72
Step 5 :
Calculating the Least Common Multiple :
5.1 Find the Least Common Multiple
The left denominator is : 3
The right denominator is : 72
Number of times each prime factor
appears in the factorization of:
Prime
Factor Left
Denominator Right
Denominator L.C.M = Max
{Left,Right}
3 1 2 2
2 0 3 3
Product of all
Prime Factors 3 72 72
Least Common Multiple:
72
Calculating Multipliers :
5.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 24
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
5.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. 2 • 24
—————————————————— = ——————
L.C.M 72
R. Mult. • R. Num. -1
—————————————————— = ——
L.C.M 72
Adding fractions that have a common denominator :
5.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
2 • 24 + -1 47
——————————— = ——
72 72
Final result :
47
—— = 0.65278
72
Answer:
After simplication value of the given term is
Step-by-step explanation:
Given,
This is a problem of fraction chapter of Algebra.
By fraction's addition and subtraction we can solve this problem easily.
And
Required value after simplication is
This is a problem of Algebra.
Some important formulas of Algebra,
(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab − b²
(a + b)³ = a³ + 3a²b + 3ab² + b³
(a - b)³ = a³ - 3a²b + 3ab² - b³
a³ + b³ = (a + b)³ − 3ab(a + b)
a³ - b³ = (a -b)³ + 3ab(a - b)