simplify 2√30/√6 - 3√140/√28 + √55/√99
Answers
Answered by
83
(2√30/√6) - (3√140/√28) + (√55/√99)
=(2√5×√6/√6) - ( 3√5×√28/√28) + (√11×√5/√11×√9)
(cancel )
= (2√5) - (3√5) + (√5/√9)
= 2√5 - 3√5 + (√5/3)
= (2-3)√5 + (√5/3)
(take common as √5)
= -1√5 + (√5/3)
(LCM OF 1 and 3 is 3)
= (-3√5+√5)/3
= (-3+1)√5/3
(take common as √5)
= -2√5/3
=(2√5×√6/√6) - ( 3√5×√28/√28) + (√11×√5/√11×√9)
(cancel )
= (2√5) - (3√5) + (√5/√9)
= 2√5 - 3√5 + (√5/3)
= (2-3)√5 + (√5/3)
(take common as √5)
= -1√5 + (√5/3)
(LCM OF 1 and 3 is 3)
= (-3√5+√5)/3
= (-3+1)√5/3
(take common as √5)
= -2√5/3
Answered by
18
Answer:
-2/3√5
Step-by-step explanation:
2√30/√6-3√140/√28+√55/√99
=(2×√5×√6) - (3√5×√28/√28) + (√11×√5/√11×√9)
[ cancel the same expression ]
= (2√5) - (3√5) + (√5/√9)
= 2√5- 3√5+ √5/3
= -1√5+√5/3
= -3√5+√5/3. {taking LCM of 3}
= -2/3√5
HOPE HELPED!
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