Question

simplify (2/3x+4)(3/2x+6)-(1/7x-1)(1/7x+1)

Answer 1

Answer:

$\dfrac{(8x + 35) (6x + 35)}{49}$

Step-by-step explanation:

$(\dfrac{2}{3}x + 4)( \dfrac{3}{2}x + 6) - (\dfrac{1}{7}x - 1)(\dfrac{1}{7}x + 1)$

Expand:

$= (\dfrac{2}{3}x)(\dfrac{3}{2}x) + (\dfrac{2}{3}x)(6) + 4(\dfrac{3}{2}x) + 4(6) - [ (\dfrac{1}{7}x)^2 - (1)^2]$

Evaluate each term:

$= x^2 + 4x + 6x + 24 - \dfrac{1}{49}x^2 +1$

Combine like terms:

$= \dfrac{48}{49}x^2 + 10x + 25$

Put into single fraction:

$= \dfrac{48x^2 + 490x + 1225}{49}$

Factorise:

$= \dfrac{(8x + 35) (6x + 35)}{49}$

Answer 2

Answer:

(8x+35)(6x+35)/49

Step-by-step explanation:

Explained in attachment