Math, asked by sumanth6, 1 year ago

simplify 2/5+3/7+(-6/5)+(-13/7)

Answers

Answered by PoojaBurra
18

Given: 2/5+3/7+(-6/5)+(-13/7)

To find: Simplify 2/5+3/7+(-6/5)+(-13/7)

Solution:

The first two fractions are positive and must be added. Also, the last two fractions are negative and hence, must be subtracted. So, the question can be rewritten as follows.

\frac{2}{5} + \frac{3}{7} - \frac{6}{5} - \frac{13}{7}

Now, the L.C.M. of the denominators of the given fractions is found. The L.C.M. of 5, 7, 5 and 7 is 35. Then, the denominators are made equal to one another as follows.

\frac{14}{35} + \frac{15}{35} - \frac{42}{35} - \frac{65}{35}

Next, the numerators are simplified and the resultant fraction is obtained.

\frac{14}{35} + \frac{15}{35} - \frac{42}{35} - \frac{65}{35} = - \frac{78}{35}

Therefore, 2/5+3/7+(-6/5)+(-13/7) = -78/35.

Answered by ramathulasi5118163
1

Step-by-step explanation:

Given: 2/5+3/7+(-6/5)+(-13/7)

To find: Simplify 2/5+3/7+(-6/5)+(-13/7)

Solution:

The first two fractions are positive and must be added. Also, the last two fractions are negative and hence, must be subtracted. So, the question can be rewritten as follows.

\frac{2}{5} + \frac{3}{7} - \frac{6}{5} - \frac{13}{7}

5

2

+

7

3

5

6

7

13

Now, the L.C.M. of the denominators of the given fractions is found. The L.C.M. of 5, 7, 5 and 7 is 35. Then, the denominators are made equal to one another as follows.

\frac{14}{35} + \frac{15}{35} - \frac{42}{35} - \frac{65}{35}

35

14

+

35

15

35

42

35

65

Next, the numerators are simplified and the resultant fraction is obtained.

\frac{14}{35} + \frac{15}{35} - \frac{42}{35} - \frac{65}{35} = - \frac{78}{35}

35

14

+

35

15

35

42

35

65

=−

35

78

Therefore, 2/5+3/7+(-6/5)+(-13/7) = -78/35.

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