Math, asked by whyareyousodumb31, 6 months ago

Simplify 2√−50+√−72
a. 2i√50+i√72
b. 16√−2
c. −16√2
d. 16i√2

Answers

Answered by mariumsiddiq98
0

Answer:

d. 16i√2

Step-by-step explanation:

___ ___ ___

2√2×5×5×i² + √2×2×2×3×3×i²

» i² = -

2×5×i√2 + 2×3×i√2

10i√2 + 6i√2

16i√2

Hope you get your answer!!

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Answered by syedaqib97
0

Answer:

D

16i \sqrt{2}

Step-by-step explanation:

For Clarification,

i = √-1

This question could be further solved as:

2i \sqrt{5 \times 5 \times 2}  + i  \sqrt{2 \times 2 \times 2 \times  3 \times 3}

2i \sqrt{ {5}^{2} }  \sqrt{2}  + i \sqrt{ {2}^{2} }  \sqrt{ {3}^{2} }  \sqrt{2}

The square root of 5, 2, and 3 will cancel out with its' squares.

So,

2i \times 5 \sqrt{2 }  + i \times 2 \times 3 \sqrt{2}

10i \sqrt{2}  + 6i \sqrt{2}

Finally,

16i \sqrt{2}

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