simplify - (2.5p-1.5q)whole to the power 2 - (1.5p-2.5q)whole to the power2
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Answered by
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We know that (a - b)^2 = a^2 + b^2 - 2ab.
Given Equation is (2.5p - 1.5q)^2 - (1.5p - 2.5q)^2.
= > [(2.5p)^2 + (1.5q)^2 - 2 * 1.5q * 2.5p] - [(1.5p)^2 + (2.5q)^2 - 2 * 1.5p * 2.5q]
= > 6.25p^2 + 2.25q^2 - 7.5pq - 2.25p^2 - 6.25q^2 + 7.5pq
= > 4p^2 - 4q^2.
Hope this helps!
Given Equation is (2.5p - 1.5q)^2 - (1.5p - 2.5q)^2.
= > [(2.5p)^2 + (1.5q)^2 - 2 * 1.5q * 2.5p] - [(1.5p)^2 + (2.5q)^2 - 2 * 1.5p * 2.5q]
= > 6.25p^2 + 2.25q^2 - 7.5pq - 2.25p^2 - 6.25q^2 + 7.5pq
= > 4p^2 - 4q^2.
Hope this helps!
kumarsuraj59ks:
how you had done last process check it again
6.25p^2 - 2.25p^2 = 4p^2
2.25q^2 - 6.25q^2 = -4q^2
Thats it!
2.25q^2 - 6.25q^2 = -4q^2
Thats it!
its correct its misunderstanding you are correct
Its okk kumar.
I understand it
thankyou siddharth
say thanks to me due me he rechecked it
thanks kumar
Hahahahaha....
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Thanx it helped me a lot. Good
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