Math, asked by harilaharypc0pwl, 1 year ago

simplify: 2/7(14x²-21y²)(-5x²-3y²)

Answers

Answered by ashishks1912
10

GIVEN :

Simplify : \frac{2}{7}(14x^2-21y^2)(-5x^2-3y^2)

TO FIND :

The simplified terms of the given expression \frac{2}{7}(14x^2-21y^2)(-5x^2-3y^2)

SOLUTION :

Given expression is \frac{2}{7}(14x^2-21y^2)(-5x^2-3y^2)

Now solving the given expression as below :

\frac{2}{7}(14x^2-21y^2)(-5x^2-3y^2)

=\frac{2}{7}(7(2x^2-3y^2))(-5x^2-3y^2)

=2(2x^2-3y^2)(-5x^2-3y^2)

=2(2x^2)-2(3y^2)(-5x^2-3y^2)

By using the Distributive property :

a(x-y)=ax-ay

=(4x^2-6y^2)(-5x^2-3y^2)

=4x^2(-5x^2-3y^2)-6y^2(-5x^2-3y^2)

By using the Distributive property :

(a+b)(x+y)=(a+b)x+(a+b)y

=4x^2(-5x^2)+4x^2(-3y^2)-6y^2(-5x^2)-6y^2(-3y^2)

By using the Distributive properties :

i) a(x+y)=ax+ay

ii) a(x-y)=ax-ay

By using the exponent property :

a^m.a^n=a^{m+n}

=-20x^4-12x^2y^2+30x^2y^2+18y^4

=-20x^4+18x^2y^2+18y^4

\frac{2}{7}(14x^2-21y^2)(-5x^2-3y^2)=-20x^4+18x^2y^2+18y^4

∴ the simplified terms for the given expression \frac{2}{7}(14x^2-21y^2)(-5x^2-3y^2) is -20x^4+18x^2y^2+18y^4

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