Question

simplify 2 cube root + 16 cube root - 54 cube root​

Answer 1

Step-by-step explanation:

$= \sqrt[3]{2} + \sqrt[3]{16} - \sqrt[3]{54} \\ = \sqrt[3]{2} + \sqrt[3]{ {2}^{3} \times 2 } - \sqrt[3]{ {3}^{3} \times 2 } \\ = \sqrt[3]{2} + 2 \sqrt[3]{2} - 3 \sqrt[3]{2} \\ = \sqrt[3]{2} (1 + 2 - 3) \\ = \sqrt[3]{2} (0) \\ = 0$

Answer 2

$\sqrt[3]{2}+\sqrt[3]{16}-\sqrt[3]{54}=0$

Step-by-step explanation:

Given : Expression $\sqrt[3]{2} + \sqrt[3]{16} - \sqrt[3]{54}$

To find : Simplify the expression ?

Solution :

Expression $\sqrt[3]{2} + \sqrt[3]{16} - \sqrt[3]{54}$

Write the numbers in factor form,

$\sqrt[3]{2} + \sqrt[3]{16}-\sqrt[3]{54}= \sqrt[3]{2} +\sqrt[3]{ {2}^{3} \times 2 }-\sqrt[3]{ {3}^{3} \times 2}$

$\sqrt[3]{2}+\sqrt[3]{16}-\sqrt[3]{54}=\sqrt[3]{2} + 2 \sqrt[3]{2} - 3 \sqrt[3]{2}$

$\sqrt[3]{2}+\sqrt[3]{16}-\sqrt[3]{54}= \sqrt[3]{2} (1 + 2 - 3)$

$\sqrt[3]{2}+\sqrt[3]{16}-\sqrt[3]{54}= \sqrt[3]{2} (0)$

$\sqrt[3]{2}+\sqrt[3]{16}-\sqrt[3]{54}=0$

#Learn more

Simplify : 2 cube root 40 + 3 Cube root 625 - 4 cube root 320​

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