Math, asked by komal2350, 1 year ago

simplify-2^n+2^n-1/2^n+1- 2^n​


komal2350: sorry it is 2^n
AbhijithPrakash: Okay lemme edit my answer
AbhijithPrakash: Wait type the equation once again..
komal2350: plz give answer of my question
AbhijithPrakash: You reported my answer by typing wrong question
komal2350: sorry it is click by mistake
AbhijithPrakash: Now is this your answer
AbhijithPrakash: ??
komal2350: no
AbhijithPrakash: Then what is your question?? Ask it clearly!!!!

Answers

Answered by AbhijithPrakash
11

Answer:

\dfrac{2^n+2^n-1}{2^n+1-2^n}=2^{1+n}-1

Step-by-step explanation:

\dfrac{2^n+2^n-1}{2^n+1-2^n}

2^n+2^n-1

\mathrm{Add\:similar\:elements:}\:2^n+2^n=2\cdot \:2^n

=2\cdot \:2^n-1

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

2\cdot \:2^n=\:2^{1+n}

=2^{n+1}-1

=\dfrac{2^{n+1}-1}{2^n+1-2^n}

\mathrm{Add\:similar\:elements:}\:2^n-2^n=0

=\dfrac{2^{n+1}-1}{1}

\mathrm{Apply\:rule}\:\dfrac{a}{1}=a

=2^{n+1}-1

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