Question

Simplify : 2 ^n + 2 ^n-1÷ 2 ^n+1 - 2 ^n.

Answer 1

Hello Friend ✌
Here is u r Ans ➡

✨
$= 2 {}^{n} + 2 {}^{n - 1} \div 2 {}^{n + 1} - 2 {}^{n}$

☄2^n or -2^n are reduced

$= 2 {}^{n - 1} \div 2 {}^{n + 1}$

$= 2 {}^{ - 2}$

$using \: > \: a {}^{ - n} = \frac{1}{a {}^{n} }$

$= \frac{1}{2 {}^{2} }$

$= \frac{1}{4}$

☄In Decimal Form ➡ 0.25 or 2^-2

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Hope This Helps u ☺

Answer 2

✨
= 2 {}^{n} + 2 {}^{n - 1} \div 2 {}^{n + 1} - 2 {}^{n}=2n+2n−1÷2n+1−2n 

☄2^n or -2^n are reduced 

= 2 {}^{n - 1} \div 2 {}^{n + 1}=2n−1÷2n+1 

= 2 {}^{ - 2}=2−2 

using \: > \: a {}^{ - n} = \frac{1}{a {}^{n} }using>a−n=an1​ 

= \frac{1}{2 {}^{2} }=221​ 

= \frac{1}{4}=41​ 

☄In Decimal Form ➡ 0.25 or 2^-2