Question

simplify 2^n+4-2(2^n)÷2(2^n+3)​

Answer 1

2^n+4-2(2^n)÷2(2^n+3)

2^n+4-4^n÷4^n+6

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Answer 2

$\bold{\huge{\fbox{\color{Maroon}{♡Hello♡}}}}$

Answer :

$2( {2}^{n}) = ( {2}^{1} ) \times ( {2}^{n} ) = {2}^{(n + 1)}$

$2(2^n+3)= (2^1) \times (2^n+3) = 2^(n + 3 + 1) = 2^(n + 4)$

=>So your equation becomes:

$[(2^n + 4) - (2^n + 1)] / (2^n + 4)$

=>If you break it up into 2 fractions, you get:

$[(2^n + 4)/(2^n + 4)] - [(2^n + 1)/(2^n + 4)]$

=>The first fraction is just 1.

=>The 2nd fraction is :

$2^(n + 1 - (n - 4)) = 2^-3 = 1/2^3 = 1/8$

=>So you get:

$\bold{\small{\fbox{\color{Black}{1 - 1/8 = 7/8}}}}$

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