Math, asked by ridamadishaikh, 7 months ago


simplify:
216÷(24-6)+2*(53-14-6)​

Answers

Answered by Yengalthilak12
19

216 \div (24 - 6) + 2 \times (53 - 14 - 6)

216 \div (18) + 2 \times (39 - 6)

0.08 3 + 2 \times (33)

0.083 + 66

66.083

Answered by NirmalPandya
5

Given:

216÷(24-6)+2*(53-14-6)

To find:

Simplification of the given expression.

Solution:

To simplify such type of expressions, we use the BODMAS rule where

B is Bracket ( ).

O is Order or Power.

D is Division.

M is Multiplication.

A is Addition.

S is Subtraction.

In this rule, the first priority is given to those numbers/terms in brackets and the least priority is for subtraction.

Here, (24-6) and (53-14-6) are given in brackets. Hence, we will simplify them first.

24-6=18

53-14-6=33

Therefore, the expression can be rewritten as 216 ÷ 18+2*33.

After the brackets, the next priority is for division since no power/order is mentioned here.

Divide 216 by 18.

216 ÷ 18=12

Substitute the value of 12 in the expression and rewriting as:

12+2*33

After division, the next priority is for multiplication. Multiply 2 with 33 to get:

2*33=66

Rewriting the expression again by substituting in the value:

12+66

Now, finally adding the two numbers to get a sum of:

12+66=78

Simplification of the expression 216÷(24-6)+2*(53-14-6) gives the answer 78.

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