Question

Simplify - 22-¼ {16-C8 +4+2)}​

Answer 1

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:d=a

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:d=a 2

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:d=a 2 −a

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:d=a 2 −a 1

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:d=a 2 −a 1 =6−1=5

The given arithmetic sequence is 1+6+11+16+....+x in which the first term is a 1 =1, second term is a 2 =6, nth term is T n =x and the sum of the series is S n =148.We find the common difference d by subtracting the first term from the second term as shown below:d=a 2 −a 1 =6−1=5+(n−1)d, therefore, with a=1,d=5 and T