Question

simplify 2a(3a^2-6b)-1/2b(2ab+8a)​

Answer 1

SOLUTION :

$\bf Simplifying \;\:\bf \therefore \:\:2a (3a^{2} - 6b)- \frac{1}{2}b(2ab+8a)\\\\= 6a^{3}-ab^{2}-16ab$

$\bf \underline{Let\:\: us \:\:solve\:\: the \:\:product}\:\: 2a (3a^{2}-6b)$

$\bf 2a(3a^{2}-6b)=2a \times 3a^{2}- 2a\times 6b\\\\=6a^{3} -12ab$

$\bf \underline{\bf Now \:\:solving \:\:the \:\:product}\:\: \frac{1}{2}b(2ab+8a),\underline{we\:\: have}$

$\bf \frac{1}{2}b(2ab+8a)=\frac{1}{2}b \times 2ab+ \frac{1}{2}b \times 8a\\\\=ab^{2}+4ab$

$\underline{\bf Now\:\:putting\:\:both \:\:the\:\: products\:\: together,}$

$\bf 2a(3a^{2}-6b)-\frac{1}{2}b(2ab+8a)$

$\bf = (6a^{3}-12ab)-(ab^{2}+4ab)$

$\bf 6a^{3}-12ab - ab^{2}-4ab$

$\bf = 6a^{3} - ab^{2}+(-12ab-4ab)\\\:\:[putting\:\: the \:\:like\:\: terms\:\: together]$

$\bf = 6a^{3}-ab^{2} -16ab$

Answer 2

Answer:

sorry but the first one is write

Step-by-step explanation:

I don't know the ans sorry

but I know you read in dav

and you doing worksheet

I also