simplify (2a-3b+4c)²
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Answer:
(2a-3b+4c)^2
(a+b+c)^2=a^2+b^2+c^2-2ab-2bc-2ca
(2a)^2+(-3b)^2+(4c)^2 - (2.2a.-3b) -(2.-3b.4c) -(2.4c.2a)
4a^2+9b^2+16c^2+12ab+24bc-16ca
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Answered by
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Step-by-step explanation:
(2a-3b+4c)² = (2a-3b+4c)(2a-3b+4c)
= (4a²-6ab+8ac-6ab+9b²-12bc+8ac-12bc+16c²)
= (4a²+9b²+16c²-12ab-24bc+16ac)
Ans..
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