Math, asked by shaikh1530, 2 months ago

Simplify : 2a (a+b–c) +3b (a–b+c) +4c (b+c–a)​

Answers

Answered by jeerubhagavanulu
1

Step-by-step explanation:

⇒ 2a−[3b−{a−(2c−3b)+4c−3(a−b−2c)}]

⇒ 2a−[3b−{a−2c+3b+4c−3a+3b+6c}]

⇒ 2a−[3b−{−2a+8c+6b}]

⇒ 2a−[3b+2a−8c−6b]

⇒ 2a−[−3b+2a−8c]

⇒ 2a+3b−2a+8c

∴ 8c+3b

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